Ask Question
5 August, 05:57

Solve for the system of linear equations x+y=4 2x+3y=0

+1
Answers (2)
  1. 5 August, 06:49
    0
    X+y=4

    2x+3y=0

    x=4-y

    2 (4-y) + 3y=0

    8-2y+3y=0

    8+y=0

    y=-8

    x + (-8) = 4

    x-8=4

    x=12
  2. 5 August, 07:15
    0
    Solve x+y=4 for x

    x+y+-y=4+-y (add - y to both sides)

    x=-y+4

    substitute - y+4 for x in 2x+3y=0

    2x+3y=0

    2 (-y+4) + 3y=0

    y+8=0 (simplify both sides of the equation)

    y+8+-8=0+-8 (add - 8 to both sides)

    y=-8

    substitute - 8 for y in x=-y+4:

    x=-y+4

    x = - (-8) + 4

    x=12 (simplify both sides of the equation)

    answer is x=12 and y=-8
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Solve for the system of linear equations x+y=4 2x+3y=0 ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers