If cos θ = 5/13, use the Pythagorean Identity to find sin θ.

13/13

12/13

12/5

5/13

Sin θ=sqrt (1 - cos^2 θ)

sin θ=sqrt[1 - (5/13) ^2]

sin θ=sqrt[1 - (5) ^2 / (13) ^2]

sin θ=sqrt[1-25/169]

sin θ=sqrt[ (169-25) / 169]

sin θ=sqrt (144/169)

sin θ=sqrt (144) / sqrt (169)

sin θ=12/13

Answer: Second option 12/13