There are 6 boys and 6 girls in a room. what is the probabilitythat the two children chosen at random will be one girl and one boy?

P (first is a boy) = 6/12 = 1/2

P (second is a girl) = 6/11

P (first boy then a girl) = 1/2 * 6/11 = 6/22 = 3/11

by a similar process P (girl then a boy) = 3/11

So the required probability = 3/11 + 3/11 = 6/11 Answer