Ask Question
8 June, 13:08

Factor 9x^6 - 16y^6 completely. First factor each term. 9x^6 = (__) 2 16y^6 = (__) 2

Then use a2 - b2 = (a - b) (a + b).

Show your work.

9x^6 - 16y^6 =

+5
Answers (1)
  1. 8 June, 15:35
    0
    See the equation they want you to use. factor to make it like that.

    9 is 3^2 and 16 is 4^2

    x^6 is (x^3) ^2

    so for the answer. factor each term

    9x^6 = (3x^3) ^2

    16y^6 = (4y^3) ^2

    see that "a" is 3x^3 and "b" is 4y^3? put it all together

    = (3x^3 - 4y^3) (3x^3 + 4y^3)
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Factor 9x^6 - 16y^6 completely. First factor each term. 9x^6 = (__) 2 16y^6 = (__) 2 Then use a2 - b2 = (a - b) (a + b). Show your work. ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers