Find 4 consecutive odd numbers such that twice the sum of the least 2 numbers is 40 less than three times the sum of the greatest two numbers

4 consecutive odd numbers ... x, x + 2, x + 4, x + 6

2 (x + x + 2) = 3 (x + 4 + x + 6) - 40

2 (2x + 2) = 3 (2x + 10) - 40

4x + 4 = 6x + 30 - 40

4x + 4 = 6x - 10

4x - 6x = - 10 - 4

-2x = - 14

x = - 14/-2

x = 7

x + 2 = 7 + 2 = 9

x + 4 = 7 + 4 = 11

x + 6 = 7 + 6 = 13

ur numbers are : 7,9,11,13 <==