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28 February, 07:19

Solve for the zeros of the quadratic function f (x) = x + 5 - 2x2. 1. Put the quadratic function in standard form. f (x) = - 2x2 + x + 5 2. Set the function equal to 0 to create a quadratic equation. - 2x2 + x + 5 = 0 3. Determine the values for a, b, and c. a = b = c = 4. Analyze the discriminant. b2 - 4ac = The quadratic function will have.

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  1. 28 February, 11:10
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    Hello:

    1)

    f (x) = x + 5 - 2x².

    the standard form is : f (x) = - 2x²+x+5

    2)

    -2x²+x+5 = 0

    3)

    a = - 2 b = 1 c=5

    4)

    the discriminant. b2 - 4ac is : (1) ²-4 (-2) (5) = 41

    the discriminant is positif:

    The quadratic function will have two roots (two solution forr the equation)
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