Ask Question
4 July, 19:42

Sinx+cosx = - sqaure root of 2

The end answer should be x=-135+360k

+1
Answers (1)
  1. 4 July, 19:53
    0
    Squaring both sides:-

    sin^2x + cos^2 x + 2 sinx cosx = 2

    1 + 2 sinx cos x = 2

    2 sinx cos x = 1

    sin2x = 1

    2x = 90 degrees

    so x = 45 degrees

    but this is not the root because the original equation has a negative right side

    sin45 + cos 45 = + sqrt2

    the only quadrant in which the sine and cosine is negative is the third quadrant

    so x = - 180 + 45 = - 135

    general case x = - 136 + 36k
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Sinx+cosx = - sqaure root of 2 The end answer should be x=-135+360k ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers