A horse race has 14 entries and one person owns 5 of the 14 horses. assuming there are no ties, what is the probability that those five horses finish first, second, third, fourth and fifth regardless of order

The key here is that there is no requirement that any specific horse of the four horses finishes in a particular place of the first four places.

The probability that any of the 4 horses finishes first is 4/14

The probability that any of the remaining 3 horses finishes second is 3/13

The probability that any of the remaining 2 horses finishes third is 2/12

And the probability that the last horse owned by this person finishes fourth is 1/11

Now multiply the probability to obtain the overall probability of these 4 four events occurring and you get

4/14 * 3/13 * 2/12 * 1/11 = 4*3*2*1 / (14*13*12*11)

Hello there.

A horse race has 14 entries and one person owns 5 of the 14 horses. assuming there are no ties, what is the probability that those five horses finish first, second, third, fourth and fifth regardless of order

=0.000999