What is the solution of the system of equations?

{13x-6y=2

3x-4y=-10

Solve the following system:

{13 x - 6 y = 2 | (equation 1)

{3 x - 4 y = - 10 | (equation 2)

Subtract 3/13 * (equation 1) from equation 2:

{13 x - 6 y = 2 | (equation 1)

{0 x - (34 y) / 13 = (-136) / 13 | (equation 2)

Multiply equation 2 by - 13/34:

{13 x - 6 y = 2 | (equation 1)

{0 x+y = 4 | (equation 2)

Add 6 * (equation 2) to equation 1:

{13 x+0 y = 26 | (equation 1)

{0 x+y = 4 | (equation 2)

Divide equation 1 by 13:

{x+0 y = 2 | (equation 1)

{0 x+y = 4 | (equation 2)

Collect results:

Answer: {x = 2 {y = 4