If f (x) = log3 (x + 1), what is f-1 (2) ?

1

8

10

27

We are asked in the problem to determine f-1 (2) given the function f (x) = log3 (x + 1). The first step is to determine the inverse of f (x).

f-1 (x):

y = log3 (x+1)

x = log3 (y+1)

3^x = y + 1

y = 3^x - 1

if x = 2

y = 8

The answer is 8 if I'm doing this right