One number is 5 more than another number. The sum of the two numbers is 43.

Let the 2 numbers be x and y.

We set up a system of equations as follows:-

x - y = 5

x + y = 43 We can solve these by the method of elimination:-

Add the 2 equations:-

2x + y + (-y) = 48

2x = 48

x = 48/2 = 24

Plug x = 24 into the first equation:-

24 - y = 5

-y = 5 - 24 = - 19

y = 19

So the 2 required numbers are 19 and 24.

Lets x and y are the 2 numbers

One number is 5 more than another number: x = y + 5

The sum of the two numbers is 43: x + y = 43

substitute x = y + 5 into x + y = 43

x + y = 43

y + 5 + y = 43

2y = 38

y = 19

x = y + 5 = 19 + 5 = 24

answer

Two numbers are 19 and 24