Gaussian surface 1 has twice the area of Gaussian surface 2. Both surfaces enclose the same charge Q. Is the electric flux through surface 1 greater than, less than, or the same as the electric flux through surface 2?

The electric flux through surface 1 is greater than the electric flux through surface 2.

Step-by-step explanation:

Electric Flux is given as:

Φ = E*A

where E = Electric field

A = surface area.

For surface 1,

Φ (1) = E (1) * A (1)

For surface 2,

Φ (2) = E (2) * A (2)

Since both surfaces have the same charge, the electric fields will be the same.

Hence, E (1) = E (2) = E

From the question we are given that:

A (1) = 0.5A (2)

Hence,

Φ (1) = E*A (1)

Φ (2) = E*A (2) = E*0.5A (1)

Φ (2) = 0.5E*A (1)

Comparing Φ (1) and Φ (2), we see that Φ (1) is 2 time greater than Φ (2), hence, the Flux through surface 1 is greater than the Flux through surface 2.