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17 June, 08:17

If the perimeter of the rectangle is 32cm and the area is 55cm2, what are the dimensions of the rectangle?

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  1. 17 June, 10:51
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    2L + 2W = 32

    L * W = 55

    L = 55/W then substitute into first equation

    2 * 55/W + 2W = 32 Multiplying both sides by "W"

    110 + 2W^2 = 32 W

    2W^2 - 32W + 110 = 0

    L = 11 or L = 5

    Also W = 11 or W = 5
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