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27 November, 10:15

If equilateral polygon penta is inscribed in a circle of radius 15 inches so that all of its vertices are on the circle, what is the length of the shorter arc from vertex p to vertex n?

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  1. 27 November, 13:19
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    The shorter arc from p to n covers 2/5 of the circumference (the longer arc would cover 3/5 of it).

    The circumference is calculated using the formula 2*pi*r

    = 2*pi * (15 inches)

    = 30*pi inches

    So the length of the arc is (2/5) * (circumference)

    = (2/5) * (30*pi)

    = 12*pi inches.
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