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3 November, 17:54

Lavinia has 9 glasses and 6 mugs. she would like to set them out in identical groups with none left over in preparation for a party. What is the greatest number of groups Lavinia can set out

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  1. 3 November, 21:28
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    You must find the factors of each number ...

    9 = 1, 3, 3, 9

    6 = 1, 2, 3, 6

    Next, determine the common multiple ...

    9 = 1, 3, 3, 9

    6 = 1, 2, 3, 6

    Therefore, the most groups Lavinia can make without any glasses or mugs left to spare is 3.
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