Website A offers tickets to an event for $4.50 each plus a $12.25 handling fee, while Website B offers the tickets for $6.00 plus a $1.75 handling fee. Find how many tickets need to be purchased in order for the cost to be the same?

9.75 because when you add 4.50 and 12.50 you'll get 16.75. Then you add 6.00 and 1.75 and get 7.75. Then you take 16 and minus it by 7 and you'll get 9 and now you add

.75 to the 9 and you'll get 9.75

The cost through each website is a linear equation (y = mx+b).

Slope (m) is a rate and the fees are the y-intercept (b).

website A.

y = 4.5x + 12.25

website B.

y = 6x + 1.75

set the cost (y) equal and solve for the number of tickets (x).

6x + 1.75 = 4.5x + 12.25

6x - 4.5x = 12.25 - 1.75

1.5x = 10.5

x = 10.5/1.5

x = 7