Four times a number minus twice another number is - 8. The sum of the two number is 19. Find the numbers

1. To solve this exercise, you must make a system of equations.

2. You have that f our times a number minus twice another number is - 8:

4x-2y=-8

3. And t he sum of the two number is 19:

x+y=19

4. As you can see, you have two equations:

4x-2y=-8 (i)

x+y=19 (ii)

5. Let's clear the "x" from the equation (ii):

x=19-y

6. Now, you need to susbtitute x=19-y into the equation (i):

4x-2y=-8

4 (19-y) - 2y=-8

76-4y-2y=-8

76-6y=-8

-6y=-8-76

-6y=-84

y=-84/-6

y=14

7. You must susbstitute y=14 into the equation (ii) and clear "x":

x+y=19

x+14=19

x=19-14

x=5

The answer is: 5 and 14