How to solve x^2-4x-5=0 by using the quadratic formula?

Factor x2 + 4x-5 x2 + 4x-5 using the AC method.

Consider the form x2 + bx+c x2 + bx+c. Find a pair of integers whose product is cc and whose sum is bb. In this case, whose product is - 5 - 5 and whose sum is 44. - 1,5=0 - 1,5=0 Write the factored form using these integers. (x-1) (x+5) = 0 (x-1) (x+5) = 0 Set x-1 x-1 equal to 00 and solve for xx.

Set the factor equal to 00. x-1=0 x-1=0 Since - 1 - 1 does not contain the variable to solve for, move it to the right side of the equation by adding 11 to both sides. x=1 x=1 Set x+5 x+5 equal to 00 and solve for xx.

Set the factor equal to 00. x+5=0 x+5=0 Since 55 does not contain the variable to solve for, move it to the right side of the equation by subtracting 55 from both sides. x=-5 x=-5 The solution is the result of x-1=0 x-1=0 and x+5=0 x+5=0. x=1, - 5