Find the area and perimeter of a triangle whose angles are all 60 degrees and base is 8m

The perimeter is 24m and the area is 64m

If the angles are all 60 degress, then the triangle must be an equilateral triangle which hse all 3 sides equal so if 1 sides is 8 in length then the other sides must be 8 in legnth also

permimiter=3 times 8=24m

area=1/2 times base times height

base=8

height=use pythagorean theorem

a^2+b^2=c^2

a=4

c=8

solve for b

4^2+b^2=8^2

16+b^2=64

subtract 16 from both sdies

b^2=48

squar root both sdies

b=4 times squareroot3=height

so 1/2 times base times height

1/2 times 8 times 4 times squareroot 3

16 times square root 3

area=4√3 meters