A recent survey by the American Cancer Society shows that the probability that someone is a smoker is P (S) = 0.19. It has also determined that the probability that someone has lung cancer, given that he or she is a smoker, is P (LC|S) = 0.158. What is the probability (rounded to the nearest hundredth) that a random person is a smoker and has lung cancer P (S ∩ LC) ?

0.03

0.83

0.35

0.02

Question

Barr

5 February, 18:25

+1

Answers (1)

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Arden · Answer 1

P (LC / S) = P (S intersect LC) / P (S)

P (S intersect LC) = P (S) * P (LC / S) = 0.19 * 0.158 = 0.03