The quadratic equation x^{2}-6x=12 is rewritten in the form (x+p) ^2=q, where q is a constant. What is the value of p?

p = - 3

Step-by-step explanation:

Given

x² - 6x = 12

To obtain the required form use the method of completing the square

add (half the coefficient of the x - term) ² to both sides, thus

x² + 2 ( - 3) x + 9 = 12 + 9

(x - 3) ² = 21

Thus p = - 3