Find the equation of the line that is perpendicular to y = 2/3

x - 5 and passes through (6, - 1).

Step-by-step explanation:

Hello:

the equation is : y = ax+b

the slope is a : a * (2/3) = - 1 ... (perpendicular to a line with a slope of 2/3 because the equation y=2/3 x - 5)

a = - 3/2 y = (-3/2) x+b

the line that passes through (6, - 1) : - 1 = (-3/2) (6) + b

b = 0

the equation is : y = (-3/2) x