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24 March, 10:00

a pyramid has a rectangular base of side 16m by14m. Given that the volume of the pyramid is 700m cube, find its height and surface area

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  1. 24 March, 10:39
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    Height of the Pyramid = 3.125 m

    The surface area of the pyramid is 635.5 sq. meters

    Step-by-step explanation:

    Here, the length and width of the rectangle = 16 m and 14 m

    Let the height of the pyramid = h m

    Volume of the pyramid = 700 cubic meters

    Volume of Rectangular Pyramid = Length x Width x Height

    or, 700 = 16 x 14 x h

    or, [tex]h = / frac{700}{14 / times 16} = 3.125[/t) ex]

    or, the Height of the Pyramid = 3.125 m

    Now, the Surface area of Rectangular Pyramid = 2 (LW + WH + HL)

    Here, Surface Area = 2 ((16 x 14) + (14 x 3.125) + (3.125 x 16))

    = 2 (224 + 43.75 + 50) = 2 x 317.75

    or, Surface Area = 635.5 sq. meters

    Hence, the surface area of the pyramid is 635.5 sq. meters
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