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3 June, 01:14

What is he range of the function y=2x^2+2 when the domain is (1,3,5)

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  1. 3 June, 03:02
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    range = (4, 20, 52)

    Step-by-step explanation:

    Substitute the given values of x from the domain into the equation and evaluate for y (the range)

    x = 1 : y = 2 (1) ² + 2 = 2 + 2 = 4

    x = 3 : y = 2 (3) ² + 2 = 18 + 2 = 20

    x = 5 : y = 2 (5) ² + 2 = 50 + 2 = 52

    range is y ∈ {4, 20, 52 }
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