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10 June, 18:04

What are the zeros of the function f (x) = x2 + 8x + 4, expressed in simplest radical form? x = - 4 ± 2StartRoot 3 EndRoot x = - 4 ± StartRoot 48 EndRoot x = StartFraction negative 8 plus or minus StartRoot 3 EndRoot Over 2 End Fraction x = StartFraction negative 4 plus or minus 4 StartRoot 3 EndRoot Over 2 End Fraction

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  1. 10 June, 19:40
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    A. on edg

    Step-by-step explanation:

    Just took the assignment.
  2. 10 June, 21:43
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    x = - 4 ± 2√ (3)

    Step-by-step explanation:

    Discriminant Δ = √ (8²-4 * (1) * (4)) = √ (48) = √ (4*12) = √ (4) * √ (12) = 2√ (12)

    then x = (-8 ± 2√ (12)) : 2 = - 4 ±√ (12) = - 4 ±√ (3*4) = - 4 ± 2√ (3)
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