Graham is hiking at an altitude of 14,040 feet and is descending 50 feet each minute. Max is hiking at an altitude of 12,500 feet and is ascending 20 feet each minute. How many minutes will it take graham and max to meet at the same altitude

Graham and max will meet after 22 minutes, with an altitude of 121,940 ft

Step-by-step explanation:

From the given example, we recall the following statements.

The altitude of Graham's hiking = 14,040 feet

He is descending 50 feet each minute.

The altitude of Max hiking = 12,500

He is ascending 20 feet each minute.

Now,

let us find how many minutes will it take graham and max to meet at the same altitude

The starting distance = 14,040-12,500 = 1,540 ft

The distance between them decreases by (50+20) ft/min = 70 ft/min

So,

1540 ft * (1 min) / (70 ft) = 22 min

Therefore, graham and max will meet after 22 minutes, and at an altitude of 121,940 ft

The answer to your question is: 51.33 min

Step-by-step explanation:

Data

Graham Max

height 14040 ft 12500 ft difference = 1540 ft

speed 50 ft/min 20 ft / min

Formula

v = d/t clear d from this equation d = vt

Equation

Graham Max

50t = 1540 + 20t

Solve it 50t - 20t = 1540

30t = 1540

t = 1540 / 30

t = 51.33 min