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10 November, 02:30

How much candy at $1.20 a pound should be mixed with candy worth 95¢ a pound in order to obtain a mixture of 50 pounds of candy worth a dollar a pound?

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  1. 10 November, 06:02
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    10 pounds of candy costing $1.20 per pounds must be mixed with 40 pounds of candy costing $ 0.95 per pound to obtain a 50 pounds of candy costing $ 1 per pound

    Solution:

    Let "x" be the pounds of candy at $ 1.20 per pound

    Then (50 - x) is the pounds of candy at $ 0.95 per pound (since 95 cents is equal to 0.95 pound)

    Therefore, x pounds of candy costing $1.20 per pounds must be mixed with (50 - x) pounds of candy costing $ 0.95 per pound to obtain a 50 pounds of candy costing $ 1 per pound

    Then the equation becomes,

    1.20x + (50 - x) 0.95 = 50 x 1

    On expanding we get,

    1.20x + 47.5 - 0.95x = 50

    0.25x = 50 - 47.5

    0.25x = 2.5

    x = 10

    Then (50 - x) = 50 - 10 = 40

    So we need 10 pounds of candy worth $ 1.20 per pound and 40 pounds of candy worth $ 0.95 to obtain 50 pounds of candy worth a dollar a pound
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