The perimeter of a rectangle can be found using the equation P = 2L + 2W, where P is the perimeter, L is the length, and

W is the width of the rectangle. Can the perimeter of the rectangle be 64 units when its width is 11 units and its length is

20 units?

Answer:NO

Step-by-step explanation:

P=2L+2w

P=2*20+2*11

P=40+22

P=62

No, that is not possible

Explanation:

P = 2L + 2W

Insert numbers into equation

p = (2) (20) + (2) (11)

Step 1: Simplify both sides of the equation.

p = (2) (20) + (2) (11)

p=40+22

p = (40+22) (Combine Like Terms)

p=62

p=62

The perimeter is 62, not 64, so the perimeter can't be 64 if the length 20 and the width is 11.