Find the value of "y" log (4y+1) = log (y-7) - 2log2

y = - 8/15

Step-by-step explanation:

log (4y + 1) = log (y - 7) - 2log2

log (4y + 1) = log (y - 7) - log2² (power law)

log (4y + 1) = log [ (y - 7) / 4]

4y + 1 = (y - 7) / 4 (remove log)

4 (4y + 1) = y - 7

16y - y = - 8

15y = - 8

y = - 8/15