Ask Question
28 February, 17:08

A population is growing at a rate proportional to its size. After four years the population was 171,000 after 19 years the population size 247,000 what was the original population calculs

+4
Answers (1)
  1. 28 February, 20:01
    0
    the initial population was 155027 people

    Step-by-step explanation:

    since the rate of increase of the population is proportional to the population itself, then the corresponding formula for a population P and time t is

    dP/dt = k*P, where k = constant

    dP/P = k*dt

    ∫dP/P = ∫ k*dt

    integrating between time t=0 (with P=P₀) and time t=t (with P=P)

    ln (P/P₀) = k*t

    if the population was P = 171000, at t=4 years then

    ln (171000/P₀) = k * 4years

    then the population is P=247000 att=19 years, thus

    ln (247000/P₀) = k*19 years

    diving both equations

    ln (247000/P₀) / ln (171000/P₀) = 19 years / 4 years

    ln (247000/P₀) = ln (171000/P₀) ^ (19/4)

    P₀/247000 = (P₀ / 171000) ^ (19/4)

    (171000) ^ (19/4) / 247000 = (P₀) ^ (19/4) / P₀ = P₀^ (15/4)

    P₀ = 171000^ (19/15) / [247000^ (4/15) ] = 155027 people

    therefore the initial population was 155027 people
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A population is growing at a rate proportional to its size. After four years the population was 171,000 after 19 years the population size ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers