Which option gives f (x) = x² - 4x - 12 rewritten in vertex form as well as the function's correct axis of symmetry?

f (x) = (x - 2) ² - 16, x = - 16

f? (x) = (x + 2) (x - 6), x = 6

f (x) = (x + 2) (x - 6), x = - 2

f (x) = (x - 2) ² - 16, x = 2

y

=

-

(

x

-

2

)

2

+

16

is the vertex form

Explanation:

The vertex form of a quadratic function is given by

y

=

a

(

x

-

h

)

2

+

k

where (h, k) is the vertex of the parabola.

when written in vertex form

(h, k) is the vertex of the parabola and x = h is the axis of symmetry

the h represents a horizontal shift (how far left, or right the graph has shifted from x = 0)

the k represents a vertical shift (how far up, or down the graph has shifted from y = 0)

Now let convert this

y

=

-

x

2

+

4

x

+

12

into vertex form

y

=

-

x

2

+

4

x

+

12

y

-

12

=

-

x

2

+

4

x

y

-

12

=

-

(

x

2

-

4

x

)

y

-

12

=

-

(

x

2

-

4

x

+

4

-

4

)

y

-

12

=

-

(

x

2

-

4

x

+

4

)

+

4

y

-

16

=

-

(

x

2

-

4

x

+

4

)

y

-

16

=

-

(

x

-

2

)

2

y

=

-

(

x

-

2

)

2

+

16

is the vertex form

show the vertex in the figure below

graph{-x^2+4x+12 [-10.06, 15.25, 6.58, 19.25]} Hope iam right