A rectangular room is 5 meters longer than it is wide and it's perimeter is 34 meters fin the dimension of the room

Step-by-step explanation:

P = 2 (L + W)

P = 34

L = W + 5

34 = 2 (W + 5 + W)

34 = 2 (2W + 5)

34 = 4W + 10

34 - 10 = 4W

24 = 4W

24/4 = W

6 = W <== = 6 meters wide

L = W + 5

L = 6 + 5

L = 11 <== = 11 meters long

Step-by-step explanation:

The length and width is unknown. What we do know is that the length is 5m longer than the width. Knowing this we can make the w = x, and the l = x + 5. This is, again, because the width is unknown and the length is the width + 5. Perimeter is 2 (l + w) (p = 2 (l + w)). We know the perimeter is equal to 34. Our equation would be 34 = 2 (l + w). Substituting the length and width for the new variables we created: 34 = 2 (x + (x + 5)). Simplified a bit this would be 34 = 2 (x + x + 5) or 34 = 2 (2x + 5) Now solve for x. x will be equal to your width and x + 5 will be equal to your l