Twice the larger of two consecutive integers is equal to fifteen less than three times the smaller. Find the integers.

17,18

Step-by-step explanation:

let the smaller integer be "a" and the larger be "b"

Then 2b = 3a - 15 ... equ 1

but they are consecutive integers, b = a+1; substitute b into equ 1, thus,

2 (a+1) = 3a - 15

2a + 2 = 3a-15

collect like terms,

2+15 = 3a-2a

17 = a

b = a+1

b = 17+1

b=18.

The integers are 17,18