What is the solution to the system of equations below? y = negative one-fourth x + 2 and 3 y = negative three-fourths x minus 6 no solution infinitely many solutions (-16, 6) (-16, - 2)

no solution

Step-by-step explanation:

Suppose the system equations are:

y = (-1/4) x + 2 (1)

3y = (-3/4) x - 6 (2)

If we multiply equation (1) by 3:

3y = (-3/4) x + 6 (1)

3y = (-3/4) x - 6 (2)

then subtract it from equation (2):

0y = 0x - 12

0 = - 12

This is not possible, therefore, the system equation has no solution