A tourist in France wants to visit 8 different cities. If the route is randomly selected, what is the probability that she will visit the cities in alphabetical order?

The answer is 0.00002480

Step-by-step explanation:

From the question stated let us recall the following statement.

The number of cities the tourist wants to visit is = 8

Now,

If the route is selected randomly, what is the probability that the cities she visits are in alphabetical order.

Therefore,

The probability that she visits the cities in alphabetical order = 1/8!

There are 8! = 40320 ways in which these cities can be visited

P (Visiting in alphabetical order) = 1/40320 = 0.00002480

Probability p (selecting 8 cities alphabetically) = 2.48*10^-5

Step-by-step explanation:

Number of possible ways of choosing 8 cities=Permutation P (n, k) = n! / (n-k) !

P (8,8) = 8! / (8-8) ! = 8! = 40,320

Probability (selecting 8 cities alphabetically) = 1/40320 = 2.48*10^-5