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5 November, 12:14

uppose that 10% of the population is taking a certain drug, and 30% of them suffer from migraines as a side effect. Supposing that the rate of migraines in the general population is 10%, what is the probability that a migraine sufferer is taking the drug?

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  1. 5 November, 12:39
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    0.3

    Step-by-step explanation:

    P (drug/migraine) = P (drug&migraine) / P (migraine)

    = (0.1*0.3) / 0.1

    = 0.3
  2. 5 November, 14:33
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    Answer:LetAbe the event that the person is taking the drug. We are told thatP (A) = 0.05. LetBbe the event that the person has migraines. We are told thatP (B) = 0.1. Further, we are told thatP (B|A) = 0.3. Using the rules for conditional probability, P (A|B) = P (A∩B) P (B) = P (B|A) P (A) P (B) = 0.3·0.050.1=0.15. The probability that a migraine sufferer takes the drug is 15%.
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