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29 April, 04:31

Is there a solution to 2x^2+7x-4=0?

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Answers (2)
  1. 29 April, 04:53
    0
    x = - 8 x = 1
  2. 29 April, 07:38
    0
    Ax^2+bx+c=0

    always answer is:

    -b + (b^2-4ac) / 2a

    and

    -b - (b^2-4ac) / 2a
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