What is the perimeter, P, of a rectangle that has a length of x + 8 and a width of y - 1?

Perimeter P of rectangle having length = x + 8 and width = y - 1 is 2x + 2y + 14.

Solution:

Need to determine perimeter P, of a rectangle.

Length of rectangle = x + 8

Width of rectangle = y - 1

As length and width are given in expressions, final result of perimeter will also be an expression.

Formula for perimeter of rectangle is as follows

Perimeter of rectangle = 2 (length + width)

On substituting given values in formula of perimeter, we get

P = 2 ((x + 8) + (y - 1))

=> P = 2 (x + 8 + y - 1)

=> P = 2 (x + y + 7)

=> p = 2x + 2y + 14

Hence perimeter P of rectangle having length = x + 8 and width = y - 1 is 2x + 2y + 14.

P = 2x + 2y + 14