Consider a population of size N = 100 with the three individual mutants with relative growth rate rA = 2, rB = 1.01, and rC = 0.99. What is the probability that each of the three mutants will take over the population?

Answer 1 / 25

Step-by-step explanation:

The probability that the first

of the three mutants will take over the population = 2 / 100

The probability that the second

of the three mutants will take over the population = 1.01 / 100

The probability that the third

of the three mutants will take over the population = 0.99 / 100

Therefore, the probability that each of the three mutants will take over the population = probability of the first, second or third = 2 / 100 + 1.01 / 100 + 0.99 / 100 = (2+1.01+0.99) / 100 = 4 / 100 = 2/25