What is an x intercept of x^2-64

Answer: (8,0) and (-8,0)

Step-by-step explanation: It is one positive and one negative 8 because a double positive would be a + 64 and a double negative would also be a + 64 (unless there was another x for example x^2+2x-64.

x^2-64

(x+8) (x-8)

(x+8) (x-8) = 0

x+8=0 and x-8=0

(-8,0) and (8,0)

(8,0) (-8,0) are the x intercepts

Step-by-step explanation:

Factor

x^2 - 64

This is the difference of squares

(x-8) (x+8)

Set equal to zero to find the intercepts

x-8 = 0 x+8 = 0

x = 8 x = - 8