Ask Question
20 February, 00:38

Events A and B are independent, Suppose event A occurs with probability 0.95 and event E occurs with probability 0.93.

a Compute the probability that neither the event A nor to event B occurs.

b Compute the probability that either B occurring A and B both occur.

+5
Answers (1)
  1. 20 February, 01:33
    0
    a) 0.0035

    b) 0.93

    Step-by-step explanation:

    P (A) = 0.95

    P (E) = 0.93

    Now,

    P (A∩E) = P (A) * P (E) = 0.95 * 0.93

    or

    P (A∩E) = 0.8835

    P (A∪E) = P (A) + P (E) - P (A∩E)

    or

    P (A∪E) = 0.95 + 0.93 - 0.8835

    or

    P (A∪E) = 0.9965

    Therefore,

    a) probability that neither the event A nor to event B occurs

    P (A'∩E') = 1 - P (A∪E)

    or

    P (A'∩E') = 1 - 0.9965 = 0.0035

    b) probability that either B occurring A and B both occur

    P ((A'∩B) ∪ (A∩E)) = P (B) = 0.93
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Events A and B are independent, Suppose event A occurs with probability 0.95 and event E occurs with probability 0.93. a Compute the ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers