h (t) = -5t^2+10t+3 is the height of a diver above the water, t seconds after the diver leaves the springboard. How high above the water is the springboard?

Question

Mathematics

Erik Pearson

20 December, 23:05

h (t) = -5t^2+10t+3 is the height of a diver above the water, t seconds after the diver leaves the springboard. How high above the water is the springboard?

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Answers (1)

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Preston Reed · Answer 1

3 units

Step-by-step explanation:

So if we want to know how high the spring board is, this will need to be the time at which the diver is still at the top of the board, in this case t = 0 seconds.

So we will need to find h (0)

h (0) = 5 (0) ² + 10 (0) + 3 = 0 + 0 + 3 = 3