Beverage A and Beverage B are sold in identical cans. Beverage A is 6% sugar. The portion of Beverage B that is sugar is 0.21. How many

times more sugar is in Beverage B than Beverage A? Write your answer as a decimal.

times more sugar

3.5 more times sugar in B

Step-by-step explanation:

We need to see that the fact that Beverage B is 0.21 sugar can be translated to percentages, just by multiplying and dividing by 100 to get it easier to see:

0.21 * 100 / 100 = 21/100 = 21% percent

This means that for every 100 units, 21 are sugar.

Now we can compare percentages directly, as both have the same volume because are sold in identical cans. We need to get how many times is 21 greater than 6. The only thing we need to do is the ratio between them:

21/6 = 3.5

This implies that 21 is 3.5 greater than 6, you can verify it by multiplying 6 by 3.5 and getting 21.

So, B has 3.5 times more sugar than A.