The area of the rectangle is 66m^2, and the length of the rectangle is 7m less than three times the width. Find the dimensions of the rectangle.

Length:

Width:

Let width=x m

so length=3x-7

Since area = 66m^2

L*B=66

(3x-7) * x=66

3x^2-7x=66

3x^2-7x-66=0

3x^2 - (18-11) x-66=0

3x^2-18x+11x-66=0

3x (x-6) + 11 (x-6) = 0

So (x-6) (3x-6) = 0

So x=2 and x=6

If x=2

Width=2

Length=2*3-7=-1

So this value of x does not exist because length cannot be negative

So x=6m

Width=6m

length=3*6-7=11m