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19 October, 07:53

Two similar figures have a side ratio of 4:3. If the perimeter of the smaller figure is 15 units, what is the perimeter of the larger figure?

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Answers (2)
  1. 19 October, 08:26
    0
    20 units

    Step-by-step explanation:

    The 3 part of the ratio refers to 15 units

    Divide 15 by 3 to find the value of one part of the ratio

    15 : 3 = 5 ← value of 1 part of the ratio, thus

    4 parts = 4 * 5 = 20 units ← perimeter of larger figure
  2. 19 October, 09:38
    0
    Answer: The answer is 20 units

    Step-by-step explanation: The question stipulates that two figures have their sides in the ratio of 4:3.

    This implies that for every side in the smaller figure, the corresponding side in the larger figure measures times 4/3 (that is, divided by 3 and then multiplied by 4)

    Therefore if for example, one side in the smaller figure measures 9 units, then the corresponding side in the larger figure would measure

    9 * 4/3.

    However, if the corresponding side is represented by x for example, then

    9/x = 3/4. (This makes the ratio of the left hand side equal to that on the right hand side)

    By cross multiplication you now have

    9 (4) = 3x

    36 = 3x

    Divide both sides of the equation by 3, and you have

    x equals 12.

    Hence, if the perimeter of the smaller figure is 15 units, the perimeter of the larger figure would be calculated as

    Perimeter of larger figure

    15/x = 3/4

    By cross multiplication you now have

    15 (4) = 3x

    60 = 3x

    Divide both sides of the equation by 3

    20 = x

    Therefore the perimeter of the larger figure is 20 units
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