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25 March, 05:02

The sum of three numbers is 61 the second number is 5 times the first while the third is 2 less than the first find the numbers

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Answers (1)
  1. P
    25 March, 08:24
    0
    9 + 45 + 7 = 61

    Step-by-step explanation:

    a+b+c = 61 ... eqn 1

    b = 5a ... eqn 2

    c = a - 2 ... eqn 3

    subst for b and c in eqn 1 ...

    => a+5a+a-2 = 61

    => 7a = 63

    => a = 9

    subst for a in eqn 2 ...

    => b = 5*9 = 45

    subst for a in eqn 3 ...

    => c = 9-2 = 7
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