3. James drives for 5 hours at a certain speed and then for 4 hours at a speed 6 km/h greater than his original speed. If he drives 294 km altogether, what was his first speed?

Answer:30km/hr

Step-by-step explanation:

Total distance=294km

Speed=s

Distance=d

Time=t

First drive:

t=5

d=s x t

d=s x 5

d=5s

Second drive:

t=4

Speed is 6km/h greater than the first speed

The new speed = s+6

d=4 (s+6)

Total distance=294

5s + 4 (s + 6) = 294

5s + 4s + 24=294

Collect like terms

5s + 4s=294 - 24

9s=270

Divide both sides by 9

9s/9=270/9

s=30

First speed=30km/hr