There are 336 students in a college who have taken a course in calculus, 227 who have take a course in discrete mathematics, and 171 who have taken a course in both calculus and discrete mathematics. How many students at this college have taken a course in either calculus or discrete mathematics?

Answer: 392

Step-by-step explanation:

Le A denotes the number of students takes calculus.

and B denotes the number of students takes discrete mathematics.

Given: There are 336 students in a college who have taken a course in calculus, 227 who have take a course in discrete mathematics, and 171 who have taken a course in both calculus and discrete mathematics.

i. e. n (A) = 336, n (B) = 227

and n (A and B) = n (A∩B) = 171

Using formula : n (A∪B) = n (A) + n (B) + n (A∩B)

⇒ n (A∪B) = 336+227-171=392

Hence, the number of students at this college have taken a course in either calculus or discrete mathematics = 392