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28 January, 17:55

The cup was filled at a

constant rate. It started empty. After 2 seconds, it held

70cm^3 of water. Find the percent of the cup that is filled

with water after 3 seconds. Use 3.14 for pi and round your

final answer to the nearest percent.

radius=4cm

high=7cm

+3
Answers (2)
  1. 28 January, 19:13
    0
    0.2986 (29.86%)

    Step-by-step explanation:

    cup volume = πr²H = 3.14 x 4² x 7 = 351.68 cm³

    after 3 minutes (70 / 2) x 3 = 105 cm³

    the percent of the cup that is filled 105/351.68 = 0.2986 (29.86%)
  2. 28 January, 20:36
    0
    its 88%
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