Ask Question
7 November, 06:17

Solve the system.

3x+2y=-2 6x-Y=-6

+1
Answers (1)
  1. 7 November, 08:03
    0
    So we assume that x=x and y=y is true for both situations so

    3x+2y=-2

    6x-y=6

    6x-y=6

    add y to both sides

    6x=6+y

    subtract 6 from both sides

    6x-6=y

    subsitute (6x-6) for y in first equation

    3x+2 (6x-6) = - 2

    distribute

    3x+12x-12=-2

    add like terms

    15x-12=-2

    add 12 to both sides

    15x=10

    divide both sides by 15

    x=2/3

    subsitute

    3x+2y=-2

    3 (2/3) + 2y=-2

    6/3+2y=-2

    2+2y=-2

    subtract 2 from both sides

    2y=-4

    divide both sides by 2

    y=-2

    x=2/3

    y=-2

    solution in (x, y) form

    (2/3,-2)
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Solve the system. 3x+2y=-2 6x-Y=-6 ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers